(2-x)/(2x^2-4x)

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Solution for (2-x)/(2x^2-4x) equation: 


D( x )

2*x^2-(4*x) = 0

2*x^2-(4*x) = 0

2*x^2-(4*x) = 0

2*x^2-4*x = 0

2*x^2-4*x = 0

DELTA = (-4)^2-(0*2*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+4)/(2*2) or x = (4-16^(1/2))/(2*2)

x = 2 or x = 0

x in (-oo:0) U (0:2) U (2:+oo)

(2-x)/(2*x^2-(4*x)) = 0

(2-x)/(2*x^2-4*x) = 0

2*x^2-4*x = 0

2*x*(x-2) = 0

x-2 = 0 // + 2

x = 2

2*x*(x-2) = 0

(2-x)/(2*x*(x-2)) = 0

2-x = 0 // - 2

-x = -2 // * -1

x = 2

x in { 2} 

x belongs to the empty set

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